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How much greater is the energy of a photon of ultraviolet radiation (wavelength=3.00x10^-7 m) than the energy of an average photon of sunlight (wavelength=5.60x10^-7 m)?

 Apr 24, 2014

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 #1
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Energy of photons is proportional to frequency, so inversely proportional to wavelength.  Therefore the ratio of ultraviolet to average energy is (1/3*10-7)/(1/5.6*10-7) = 5.6/3 (because the 10-7s cancel).  So ultraviolet energy is 

5.63=1.8666666666666667times greater than the average.

 Apr 25, 2014
 #1
avatar+33654 
+5
Best Answer

Energy of photons is proportional to frequency, so inversely proportional to wavelength.  Therefore the ratio of ultraviolet to average energy is (1/3*10-7)/(1/5.6*10-7) = 5.6/3 (because the 10-7s cancel).  So ultraviolet energy is 

5.63=1.8666666666666667times greater than the average.

Alan Apr 25, 2014

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