if there is a right triangle ABC and the tangent B is 8/15 what is the cosine of A
The tangent is opposite over adjacent, so if we let opposite be 8 and adjacent be 15 then the hypotenuse is
√82+152=17
cosine is adjacent over hypotenuse, so cos(B) = 15/17. Angle A must be the other angle (not the right-angle) so we must have cos(A) = 8/17.
Even if the sides are not actually 8, 15 and 17 they must all be a scale factor times those values. The scale factor will cancel out of the ratios when determining cos, sin and tan.
The tangent is opposite over adjacent, so if we let opposite be 8 and adjacent be 15 then the hypotenuse is
√82+152=17
cosine is adjacent over hypotenuse, so cos(B) = 15/17. Angle A must be the other angle (not the right-angle) so we must have cos(A) = 8/17.
Even if the sides are not actually 8, 15 and 17 they must all be a scale factor times those values. The scale factor will cancel out of the ratios when determining cos, sin and tan.