If x ≥ 2 and y ≥ -3 what is then the smallest value 2*x + y^2 can have?

X can equal 4 and y can equal -2

$${\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\left(-{\mathtt{2}}\right)}^{{\mathtt{2}}} = {\mathtt{12}}$$

Shouldnt it be x = 2 and y = 1. Then you get the answer 5.
2*2 + 1^2 = 5

x is greater than 2.....so 3...and y can be 0

$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{3}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{0}}}^{{\mathtt{2}}} = {\mathtt{6}}$$