in a club with 9 male and 11 female members, how man 5-member committees can be chosen to have
a.) all men
b.) all women
c.)3 men and 2 women
+23254 1) You are choosing 5 members from a group of 9 males and 0 members from a group of 11 females:
9nCr5 · 11nCr0 =
2) You are choosing 0 members from a group of 9 males and 5 members from a group of 11 females:
9nCr0 · 11nCr5 =
3) You are choosing 3 members from a group of 9 males and 2 members from a group of 11 females:
9nCr3 · 11nCr2 =
+23254 1) You are choosing 5 members from a group of 9 males and 0 members from a group of 11 females:
9nCr5 · 11nCr0 =
2) You are choosing 0 members from a group of 9 males and 5 members from a group of 11 females:
9nCr0 · 11nCr5 =
3) You are choosing 3 members from a group of 9 males and 2 members from a group of 11 females:
9nCr3 · 11nCr2 =
