In the triangle ABC B=90 DEGREE AC=60CM AND BC=22 CM FIND ANGLE C

In that right triangle, the side BC is adjacent to ∠C and the hypotenuse is side AC.

If you know the adjacent and the hypotenuse, use the cosine:  cosine = adjacent / hypotenuse.

cos(C)  =  22 / 60     --->     cos(C)  =  0.36667

Find the invcos of both sides     --->   C  =  invcos(0.366667)  =  68.5°.

In triangle XYZ  X=90 DEGREE YZ=1.6CM AND XY=1.32cm find angle z