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Roots = 4, 5, 7, 9

 

Equation  -  f(x) = (x-4)(x-5)(x-7)(x-9)

                  f(x) = (x^2-12x+35)(x^2-13x+36)

                  f(x) = x^4 - 25x^3 + 227x^2 - 887x + 1260

 

Now substitute. Does the function make analytical sense in a mathematical perspective (Is it right?) ?

Now multiply the function by x^2 +x. Is the equation this?:

 

f(x) = x^6 - 24x^5 + 202x^4 - 660x^3 + 373x^2 + 1260x

 

Now multiply the function by (1-x). Does it equal this?:

f(x) = -x^7 + 25x^6 - 226x^5 + 862x^4 - 1033x^3 - 887x^2 + 1260x

 

Then find roots.

 

#YOLO

THX

Like Math, Just Wondering. Do this and you are a champion.

 Oct 14, 2014

Best Answer 

 #1
avatar+23254 
+5

If you start with  (x - 4)(x - 5) (x - 7) (x - 9)     and multiply by    x² + x (which is x(x + 1) )

and multiply by    1 - x

The roots will be the values that make the original factors zero; specifically,  4, 5, 7, 9, 0, -1, and 1.

 Oct 14, 2014
 #1
avatar+23254 
+5
Best Answer

If you start with  (x - 4)(x - 5) (x - 7) (x - 9)     and multiply by    x² + x (which is x(x + 1) )

and multiply by    1 - x

The roots will be the values that make the original factors zero; specifically,  4, 5, 7, 9, 0, -1, and 1.

geno3141 Oct 14, 2014

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