solve by elimination method
2x-5y=3
-2/5x+y=3/10
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solve the system of equations
3x+4y=15
2x-5z=-3
4y-3z=9
The first set has no solutions (Multiply the second equation by -5 and you get 2x -5y = -3/2 which cannot hold at the same time as 2x - 5y = 3)
I entered the wrong data in the matrix approach! But since that approach isn't one you understand, here's how to do it by a process of elimination: