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Why is \(\displaystyle \lim_{x\rightarrow \infty}\left(1+\dfrac{2}{x}\right)^x=e^2\)?

 Aug 24, 2016

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See reply at http://web2.0calc.com/questions/wow-i-don-t-know-how-to-take-this-limit#r4 

 Aug 24, 2016
 #1
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See reply at http://web2.0calc.com/questions/wow-i-don-t-know-how-to-take-this-limit#r4 

Alan Aug 24, 2016

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