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Log 5 (3x-7)=3

 Aug 28, 2014

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 #1
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I assume this is log5 (3x-7) = 3

5^3 = 3x - 7

125 = 3x - 7

 

From here, it should be simple algebra! 

 Aug 29, 2014
 #1
avatar+4473 
+5
Best Answer

I assume this is log5 (3x-7) = 3

5^3 = 3x - 7

125 = 3x - 7

 

From here, it should be simple algebra! 

AzizHusain Aug 29, 2014

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