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log(e1+2i)

Here i mean log base 10 not base e

 Aug 17, 2016
 #1
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(1+2 i)/(log(10))

=0.43429448190325182765112891891660508229439700580366656611... +
0.86858896380650365530225783783321016458879401160733313222... i

 Aug 17, 2016
 #2
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This looks hard but I will give it a try.

Let x=log(e(1+2i))10x=e1+2i10x=e×(ei)2

 

 

eiπ+1=0(ei)π+1=0(ei)π=1ei=(1)1π

 

10x=e×(1)2π10x=e×(1)1π10x=ex=loge

 Aug 17, 2016

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