log(e1+2i)
Here i mean log base 10 not base e
(1+2 i)/(log(10))
=0.43429448190325182765112891891660508229439700580366656611... + 0.86858896380650365530225783783321016458879401160733313222... i
This looks hard but I will give it a try.
Let x=log(e(1+2i))10x=e1+2i10x=e×(ei)2
eiπ+1=0(ei)π+1=0(ei)π=−1ei=(−1)1π
10x=e×(−1)2π10x=e×(1)1π10x=ex=loge