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Hey guys,

I'm having some trouble with this one Physics question. Can you help?

 

A man drops a stone into a mineshaft 180 meters deep. If the temperature is 20 degrees Celcius, how much time will elapse between the moment when the stone is dropped and the moment when the sound of the stone hitting the bottom of the mine shaft is heard?

 

The formulae that we used in the lesson are:

speed of air= 332+0.6(Temperature)

velocity=change in displacement/change in time            (equation above used in refernce to echos. Remember that echos are a two-way thing. For example, the distance an echo travels involves the distance to a wall, and back.)

 Oct 17, 2014

Best Answer 

 #1
avatar+23254 
+5

Speed in air = 332 + 0.6(20)  = 338 m/s

Time for stone to drop:

s = -4.9t²

-180 = -4.9t²

t = 6.06 sec

Time for sound to come back:

D = R x T

180m = 338m/s x T

0.53 sec  =  T

Total time:  6.06 + 0.53  =  6/59 sec

 Oct 17, 2014
 #1
avatar+23254 
+5
Best Answer

Speed in air = 332 + 0.6(20)  = 338 m/s

Time for stone to drop:

s = -4.9t²

-180 = -4.9t²

t = 6.06 sec

Time for sound to come back:

D = R x T

180m = 338m/s x T

0.53 sec  =  T

Total time:  6.06 + 0.53  =  6/59 sec

geno3141 Oct 17, 2014

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