Pls help me thank you!!!

Hello BIGChungus!  I like your name!
 

Plan:

For arithmetic problems, I like using variables.

First term = x

Common difference = y

We can define an arithmetic sequence this way:

x + (x + y) + (x + 2y) + (x + 3y)....

Set up and solve:

(1) $\frac{a_4}{a_2}=\frac{x+3y}{x+y}=3$

(2) $\frac{a_5}{a_3}=\frac{x+4y}{x+2y}=?$

Let us get rid of the fraction in (1) by multiplying both sides by (x+y)

x + 3y = 3x + 3y

-2x = 0

x = 0

Wow! The first term is 0.

Let us plug that into (2).

$\frac{0+4y}{0+2y}$

Simplify

$\frac{4y}{2y}=2$

Ta-da! Mathz! 

thx man and I love my name to XD