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Solution for [4-(3c-1)][6-(3c-1)]

 Nov 14, 2014

Best Answer 

 #1
avatar+23254 
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[4 - (3c - 1)][6 - (3c - 1)]

=  [4 - 3c + 1][6 - 3c + 1]

=  [5 - 3c][7 - 3c]

=  35 - 21c - 15c + 9c²

=  35 - 36c + 9c²

 Nov 15, 2014
 #1
avatar+23254 
+5
Best Answer

[4 - (3c - 1)][6 - (3c - 1)]

=  [4 - 3c + 1][6 - 3c + 1]

=  [5 - 3c][7 - 3c]

=  35 - 21c - 15c + 9c²

=  35 - 36c + 9c²

geno3141 Nov 15, 2014
 #2
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Thank you so much! 

 Nov 15, 2014

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