Probability

The probability that the first student chosen is a boy is  1/6.

Now, there are only 5 boys remaining, so the probability that te second student chosen is a boy is  1/5.

Combine these two probabilities by multiplying  (1/6) x (1/5)  =  1/30.

There is a $6 \over 13$ chance of picking a boy the first time (6 boys over 13 total students)

After that, there is a $5 \over 12$ chance of picking a boy (5 boys, 1 was chosen, over 12 remaining students)

Thus, the total probability is ${6 \over 13} \times {5 \over 12} = \color{brown}\boxed{5 \over 26}$