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QA1. Draw the graph of relation defined by:  y^2 = 2x

 Oct 16, 2014

Best Answer 

 #2
avatar+130477 
+5

Geno's method will work....but here's something that might be easier........ using...... y^2 = 2x

Divide both sides by 2...so we have

y^2/2  = x

Now, nstead of selecting "x" values, just select a few y values.....I suggest 0, 2, 4, 6 and -2,-4, -6 ....and find the associated "x" for each one......we don't have to take any square roots that way...

If you do this correctly...you should end up with  parabola facing to the "right" with its vertex  at the origin !!!

 

 Oct 16, 2014
 #1
avatar+23254 
+5

You can do this by plotting points:

  x  |   y                                 Complete this table; some of the values for x will have no values for y.

_______                                Also, because you need to find square roots, many of these will have

-9  |                                      two answer, one + and one -.

-4  |

-1  |

 0  |

 1  |

 4  |

 9  |

 Oct 16, 2014
 #2
avatar+130477 
+5
Best Answer

Geno's method will work....but here's something that might be easier........ using...... y^2 = 2x

Divide both sides by 2...so we have

y^2/2  = x

Now, nstead of selecting "x" values, just select a few y values.....I suggest 0, 2, 4, 6 and -2,-4, -6 ....and find the associated "x" for each one......we don't have to take any square roots that way...

If you do this correctly...you should end up with  parabola facing to the "right" with its vertex  at the origin !!!

 

CPhill Oct 16, 2014

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