A cup of coffee is sitting on a table in an airplane that is flying at a constant altitude and a constant velocity.
The coefficient of static friction between the cup and the table is 0.42. Suddenly, the plane accelerates, its altitude remaining constant.
What is the maximum acceleration that the plane can have without the cup sliding backward on the table?
+33657 The force needed to get the cup to slip is 0.42*cupmass*gravitational acceleration. This must equal cupmass*accelerationof plane. Therefore:
acceleration of plane = 0.42*9.81 m/s2 (assuming plane isn't so high gravitational acceleration is significantly reduced!), as the mass of the cup cancels out.
AccnOfPlane=0.42×9.81⇒AccnOfPlane=4.1202 m/s2
+33657 The force needed to get the cup to slip is 0.42*cupmass*gravitational acceleration. This must equal cupmass*accelerationof plane. Therefore:
acceleration of plane = 0.42*9.81 m/s2 (assuming plane isn't so high gravitational acceleration is significantly reduced!), as the mass of the cup cancels out.
AccnOfPlane=0.42×9.81⇒AccnOfPlane=4.1202 m/s2
