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I need help showing that this is true: sin^4A-cos^4A=1-2cos^2A 

 May 26, 2014

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 #1
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\sin^4{A}-\cos^4{A}=(\sin^2{A}-\cos^2{A})(\sin^2{A}+\cos^2{A})\sin^2{A}+\cos^2{A}=1\sin^2{A}-\cos^2{A}=1-\cos^2{A}-\cos^2{A}=1-2\cos^2{A}So,usingthelasttwolinesinthefirstlinewehave:\sin^4{A}-\cos^4{A}=1-2\cos^2{A}$$

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 May 26, 2014
 #1
avatar+33654 
+8
Best Answer

\sin^4{A}-\cos^4{A}=(\sin^2{A}-\cos^2{A})(\sin^2{A}+\cos^2{A})\sin^2{A}+\cos^2{A}=1\sin^2{A}-\cos^2{A}=1-\cos^2{A}-\cos^2{A}=1-2\cos^2{A}So,usingthelasttwolinesinthefirstlinewehave:\sin^4{A}-\cos^4{A}=1-2\cos^2{A}$$

Alan May 26, 2014

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