Solve. 10p^2-41p=0?

$${\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{p}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{41}}{\mathtt{\,\times\,}}{\mathtt{p}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\frac{{\mathtt{41}}}{{\mathtt{10}}}}\\ {\mathtt{p}} = {\mathtt{0}}\\ \end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\mathtt{4.1}}\\ {\mathtt{p}} = {\mathtt{0}}\\ \end{array} \right\}$$