Solve and round to the nearest thousandth.

If the variable is in the exponent, use logs:

2^(3x - 4)  =  5

log[ 2^(3x - 4) ]  =  log(5)

The reason for using logs: the exponent comes out as a multiplier:

(3x-4)·log(2)  =  log(5)

Divide by log(2);

   3x - 4  =  log(5) / log(2)

   3x  =   log(5) / log(2) + 4

     x  =  ( log(5) / log(2) + 4) / 3

Your equation is hard to read, do you mean:

3x-4=5?

3x-4^2=5?

No it is exponets

When it says round to the nearest thousandth would that makw it 2.107