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Stuck on factoring equations.

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Hey guys, expanding factored equations and simplifying them has my head in a knot.

Any extremely helpful advice to get past it? (no need to resolve except for the last couple if you're generous.)

The questions format is varied, ie.
(2-x)(1-x) (struggling)

(3x-9y) -> got this type easily.

(1/2x + 1/4y) -> i got 1/4(1/4x+y) but think it's wrong.

(3x+1)(2x+1) -> which posed the question, how do I know if a number attributed to x or just a solo number was factored? (struggling)

1/3x + 1/6xy -> have not really attempted this in the last few days. But I can do it.

2/3pi 3+1/3pi 2h. -> do solve please. I get that pi can be same as x in the equation but that isn't my issue trying to solve it.


also

2x 2(x-5)-x(x-2)-3x(x-5)

5x 2-4x-1 (can solve with lots of thoughts.

16x 2-1

Would love advice and ideas to solve.
 Feb 8, 2014

4+0 Answers

 #1
avatar+6248 
0
Quote:

Hey guys, expanding factored equations and simplifying them has my head in a knot.

Any extremely helpful advice to get past it? (no need to resolve except for the last couple if you're generous.)

The questions format is varied, ie.
(2-x)(1-x) (struggling)

(3x-9y) -> got this type easily.

(1/2x + 1/4y) -> i got 1/4(1/4x+y) but think it's wrong.



it is. You can't afford to not be able to do simple arithmetic like this if you're going into EE.

(1/2x + 1/4y) = 1/4(2x + y)

Quote:


(3x+1)(2x+1) -> which posed the question, how do I know if a number attributed to x or just a solo number was factored? (struggling)



this is already factored. I'm not sure what you are asking here.


Quote:


1/3x + 1/6xy -> have not really attempted this in the last few days. But I can do it.

2/3pi3+1/3pi2h. -> do solve please. I get that pi can be same as x in the equation but that isn't my issue trying to solve it.



I don't know what this is. do you mean

(2/3) pi 3 + (1/3) pi 2h ?

if so it's (1/3)pi 2(2pi + h)

Quote:


also

2x2(x-5)-x(x-2)-3x(x-5)



this is just arithmetic. just multiply everything out.

Quote:


5x2-4x-1 (can solve with lots of thoughts.



(5x+1)(x-1)

Quote:


16x2-1



difference of 2 squares
(4x-1)(4x+1)

my advice to you is to practice these types of problems until you can do them as easily as you can add 2 and 2.
If you can't whip through this sort of stuff pre-calculus is going to be h**l.
 Feb 8, 2014
 #2
avatar+1313 
0
(3x+1)(2x+1) = 6x 2+5x+1 -> which posed the question, how do I know if a number attributed to x was factored or it was the whole number with no x that was factored.

Thanks for advice and yes, I will know it. Just getting on top of it so seeking some thoughts to more easily solve than I can. Just getting mixed up atm and only brushed over it in my little bit of study help. Still a couple weeks to practice left.
 Feb 8, 2014
 #3
avatar+118609 
0
Stu:

(3x+1)(2x+1) = 6x2+5x+1 -> which posed the question, how do I know if a number attributed to x was factored or it was the whole number with no x that was factored.

Thanks for advice and yes, I will know it. Just getting on top of it so seeking some thoughts to more easily solve than I can. Just getting mixed up atm and only brushed over it in my little bit of study help. Still a couple weeks to practice left.



I don't understand what you mean Stu. Maybe if I read all the other posts I might.

This has been simplified not factorised.
When you factorise you put the brackets in
when you simplify you take the brackets out.
 Feb 8, 2014
 #4
avatar+1313 
0
my bad. The question was to expand for that instance. But I grouped my questions broadly under one post - factoring. Sorry.
 Feb 8, 2014

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