The mass of a single silver atom is 1.79E-22 grams. How many silver atoms would there be in 49.3 milligrams of silver?

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Guest Aug 29, 2014

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Best Answer

49.3 milligrams is 49.3*10^-3 grams;

so number of atoms = 49.3*10^-3/(1.79*10^-22) = 49.3*10¹⁹/1.79 ≈ 2.75*10²⁰ atoms

Alan Aug 29, 2014

Alan · Answer 1 · 2014-08-29T01:45:25

49.3 milligrams is 49.3*10^-3 grams;

so number of atoms = 49.3*10^-3/(1.79*10^-22) = 49.3*10¹⁹/1.79 ≈ 2.75*10²⁰ atoms