| The wavelength of a specific photon in the infrared spectrum is 4 × 10-6 meters. Given that the speed of light is 2.998 × 108 m/s, what wo

$${\mathtt{f}} = {\frac{{\mathtt{2.998}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{8}}}}{\left({\mathtt{4}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}} \Rightarrow {\mathtt{f}} = {\mathtt{74\,950\,000\,000\,000}}$$

or f = 0.7495*10¹⁴ Hz

The wavelength should have 10^-6 NinjaDevo, not 10⁺⁶.

I'm interpreting all these as 10^something.

I think this is what you meant because you said "given the speed of light is 2.998x108 m/sec", and 2.998x10⁸ m/sec is the approximate speed of light.

Here is our equation to figure out the frequency of a wave:

f = V / λ

Where

f = frequency

V= velocity of the photon (speed of light)

λ = Wavelegnth

---------------

f = V / λ

f = (2.998 × 10⁸ m/s) ÷ (4 × 10⁶ m)

f = (2.998 × 10⁸ m/s) ÷ (4 × 10⁶ m)           ---Meters calcels

f = (2.998 × 10⁸ s) ÷ (4 × 10⁶)

f = (2.998 ÷ 4)( 10⁸ s ÷ 10⁶)

f = (.7495)(10² s)

f = .7495*10² s

".7495*10² seconds" doesn't make much sence. It turns out when your dealing with questions like this, that second = Hz. So...

f = .7495*10² Hz

This doesn't match one of your answers...I'm abit stumped on this myself. Any of mathematicians want to double check my work here...?

Ohh! Thanks Alan.

I was thinking by the - symbol he meant a ^ symbol...but he really meant a minus sign!

This makes more sence, because I checked my work literally like 5 times and didn't find an error! :)