If a piece of sheet metals with lengths 10 in., 13 in., and 14 in. weighs 1.7 ounces per square inch, how much does the triangle weigh?
We need to find the area. Given three sides, we can use Heron's formula:
Area = √[ s·(s - a)·(s - b)·(s - c) ] where the semiperimeter s = (a + b + c) / 2
a = 10 b = 13 c = 14
---> s = (10 + 13 + 14) / 2 = 18.5
---> Area = √[ 18.5·(18.5 - 10)·(18.5 - 13)·(18.5 - 14) ] = 62.4
---> Weight = 62.4 x 1.7 = 106 ounces
We need to find the area. Given three sides, we can use Heron's formula:
Area = √[ s·(s - a)·(s - b)·(s - c) ] where the semiperimeter s = (a + b + c) / 2
a = 10 b = 13 c = 14
---> s = (10 + 13 + 14) / 2 = 18.5
---> Area = √[ 18.5·(18.5 - 10)·(18.5 - 13)·(18.5 - 14) ] = 62.4
---> Weight = 62.4 x 1.7 = 106 ounces