The height of the water at a pier on a certain day can be modeled by this formula, where h is the height in feet and t is the time in hours after midnight. When is the first time the height of the water reaches 6 feet? (Hint: Substitute 6 for h and find t. Convert the value you find for t to hours and minutes. For example, 5.5 represents 5:30 am.)
A) 1:14 am
B) 4:25 pm
C) 3:47 am
D) 2:12 am
+23254 6 = 4.8sin[ (π/6)(t + 3.5) ] + 9
-3 = 4.8sin[ (π/6)(t + 3.5) ] subtract 9
-0.625 = sin[ (π/6)(t + 3.5) ] divide by 4.8
-.675 = (π/6)(t + 3.5) invserse sin
-.675 radians will be equivalent to 5.608 radians 2π - .675
For sin, -.675 radians is also equaivalent to 3.817 radians π +.675
Using 3.817 = (π/6)(t + 3.5)
22.902 = π(t + 3.5) multiply by 6
7.29 = t + 3.5 divide by π
3.79 = t subtract 3.5
.79 x 60 = 47 ---> 3:47 a.m.
+23254 6 = 4.8sin[ (π/6)(t + 3.5) ] + 9
-3 = 4.8sin[ (π/6)(t + 3.5) ] subtract 9
-0.625 = sin[ (π/6)(t + 3.5) ] divide by 4.8
-.675 = (π/6)(t + 3.5) invserse sin
-.675 radians will be equivalent to 5.608 radians 2π - .675
For sin, -.675 radians is also equaivalent to 3.817 radians π +.675
Using 3.817 = (π/6)(t + 3.5)
22.902 = π(t + 3.5) multiply by 6
7.29 = t + 3.5 divide by π
3.79 = t subtract 3.5
.79 x 60 = 47 ---> 3:47 a.m.
