You lay on the ground shooting Velcro b***s at a velcro wall 30m away. the b***s leave the gun at the inital speed of 23m/s and you are aiming at a 35º angle. How high above the ground will the b***s stick to the wall?
Initially t=0
¨x=0˙x=23cos350x=0¨y=−9.8˙y=23sin350y=0
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Ongoing
¨x=0˙x=23cos350x=(23cos350)t | ¨y=−9.8˙y=−9.8t+23sin350y=−9.8t22+(23sin350)ty=−4.9t2+(23sin350)t |
Find y when x=30
When x=30
30=(23cos35)t
t=30/(23cos35)
t=1.592314681
−4.9×1.5923146812+23×sin360∘(35∘)×1.592314681=8.5824425340714199
The ball will hit the wall 8.58 metres above the floor.
Initially t=0
¨x=0˙x=23cos350x=0¨y=−9.8˙y=23sin350y=0
------------------------------------------------------------------
Ongoing
¨x=0˙x=23cos350x=(23cos350)t | ¨y=−9.8˙y=−9.8t+23sin350y=−9.8t22+(23sin350)ty=−4.9t2+(23sin350)t |
Find y when x=30
When x=30
30=(23cos35)t
t=30/(23cos35)
t=1.592314681
−4.9×1.5923146812+23×sin360∘(35∘)×1.592314681=8.5824425340714199
The ball will hit the wall 8.58 metres above the floor.