To emphasize what Melody did:
The equation: |3x| + |4y| = 12
Can be split into 4 separate equations; 2 for the |3x| = ± 3x and 2 for the |4y| = ± 4y :
---> 3x + 4y = 12 ---> y = (12 - 3x)/4
-3x + 4y = 12 ---> y = (12 + 3x)/4
3x - 4y = 12 ---> y = (12 - 3x)/-4
-3x - 4y = 12 ---> y = (12 + 3x)/-4
Graphing these individually will give you the parallelogram that Melody got.
I 'cheated' a bit because I ran off and graphed it.
Here is the graph.
https://www.desmos.com/calculator/rrxgm9spsh
I expected it to be a parallelogram and it was.
(I can talk more about this if you want me too)
The easiest way to find the area is to split it into 2 congruent trianges
base = 8 units and height = 3 units
Area = 2×(12×8×3)=24 units squared.
Note the graph.......https://www.desmos.com/calculator/dbrn6oivcb
These are two triangles which have a base = 8 and a height = 3
So, the area is just 2(1/2)(8)(3) = 24 units
Melody and I both cheated...(but she cheated first.....and as chief mod, she should set a BETTER EXAMPLE to the people of Camelot!!!)...LOL!!!!
To emphasize what Melody did:
The equation: |3x| + |4y| = 12
Can be split into 4 separate equations; 2 for the |3x| = ± 3x and 2 for the |4y| = ± 4y :
---> 3x + 4y = 12 ---> y = (12 - 3x)/4
-3x + 4y = 12 ---> y = (12 + 3x)/4
3x - 4y = 12 ---> y = (12 - 3x)/-4
-3x - 4y = 12 ---> y = (12 + 3x)/-4
Graphing these individually will give you the parallelogram that Melody got.