what is the phase shift

y=a(sin[n(x+p)])

phase shift is p units to the left  (neg direction)

The phase shift for this equation is how far the graph is moved to the left or right of   y=a(sin(nx))

notice how I took the n outside of the bracket. So if it was presented like this

y=a(sin[nx+np])

you need to factor out the n to get the phase shift.    

You try

y=6cos(7x+5)

What will the phase shift be?     

**By the way, all angles are in radians**

A phase shift is a horizontal shift in a function; often, trig functions.

For instance, the basis sin function is  y = sin(x).

 If you have this equation y = sin(x - π/2)  (in radians, 90° if in degrees),

  you have a horizontal shift of the graph π/2 units to the right.

The equation y = cos(x + π) is the graph of y = cos(x) shifted π units to the left.

Yes:  if it's x - a, move the whole graph to the right a units; if it's x + a, move it to the left a units.