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whats the rule for my table?

-4  6

 4  4

 8  3

12 2

and what is an equation for the rule?

 Dec 3, 2014

Best Answer 

 #6
avatar+26396 
+5

whats the rule for my table?

-4  6

 4  4

 8  3

12 2

and what is an equation for the rule?

\small\text{ \begin{array}{c|c|c} \hline  n & a_n & \small{\text{difference (d)}} \\ \hline  1 & 16 & \\ & & -4\\ 2 & 12 \\  & & -4\\ 3 & 8 \\ & & -4\\ 4 & 4 \\ & & -4\\ 5 & 0 \\ & & -4\\ 6 & -4 \\ \hline \end{array} }}

an=a1+(n1)d arithmetic series 

a1=16 and d=4an=16+(n1)(4)an=164n+4an=204nThe equation for an is an=204nn?an=204n4n=20an|:4n=514anThe equation for n is 514an

 Dec 3, 2014
 #1
avatar+23254 
+5

The formula for slope is:  m  =  (y2 - y1) / (x2 - x1)

The slope from (-4, 6) to (4, 4) is:  m  =  (4 - 6) / (4 - -4)  =  -2/8  =  -1/4

The slope from (4, 4) to (8, 3) is:  m  =  (3 - 4) / (8 - 4)  =  -1/4 

The slope from (8, 3) to (12, 2) is:  m  =  (2 - 3) / (12 - 8)  =  -1/4

Since the slope is always the same, these points fall on a straight line.

The point-slope formula for a straight line is:  y - y1  =  m(x - x1)

Using (x1, y1) = (-4, 6) and m = -1/4:          y - 6  =  (-1/4)(x - -4)

                                                                       y - 6  =  (-1/4)(x + 4)

                                                                        y - 6  =  (-1/4)x - 1

                                                                        y  =  (-1/4)x + 5

Melody, you are correct, so I'll modify my answer.

 Dec 3, 2014
 #2
avatar+118703 
+5

I think it is just

y= -1/4x+5

 Dec 3, 2014
 #3
avatar+1090 
+5

If geno3141 is correct, wouldn't it simplify further to y  =  (-1/4)x + 11?

 Dec 3, 2014
 #4
avatar
+5

thank you guys sooo much got er' down! thanks again!

 Dec 3, 2014
 #5
avatar+1090 
+5

First let me test the rule:

0.25×(4)+5=6

0.25×(4)+5=4

0.25×(8)+5=3

0.25×(4)+5=6

It looks like Melody is accurate.

 Dec 3, 2014
 #6
avatar+26396 
+5
Best Answer

whats the rule for my table?

-4  6

 4  4

 8  3

12 2

and what is an equation for the rule?

\small\text{ \begin{array}{c|c|c} \hline  n & a_n & \small{\text{difference (d)}} \\ \hline  1 & 16 & \\ & & -4\\ 2 & 12 \\  & & -4\\ 3 & 8 \\ & & -4\\ 4 & 4 \\ & & -4\\ 5 & 0 \\ & & -4\\ 6 & -4 \\ \hline \end{array} }}

an=a1+(n1)d arithmetic series 

a1=16 and d=4an=16+(n1)(4)an=164n+4an=204nThe equation for an is an=204nn?an=204n4n=20an|:4n=514anThe equation for n is 514an

heureka Dec 3, 2014

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