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solve for x in the eqiation x^(-2/3)=(-1/9)

 Oct 29, 2014

Best Answer 

 #1
avatar+23254 
+5

Remove the negative exponent:  x^(-2/3)  =  1 / x^(2/3)

1 /  x^(2/3)  =  -1/9

Cross multiply:  9  =  -x^(2/3)

-9  =  x^(2/3)          This means the cube root of x squared, so

cube both sides:

(-9) ^3  =  x^2

-729  =  x^2

If you are restricted to real numbers, this is impossible. However, if you can use complex numbers:

Find the square root of both sides:

x  =  ±√(-729)  =  ±27i

 Oct 29, 2014
 #1
avatar+23254 
+5
Best Answer

Remove the negative exponent:  x^(-2/3)  =  1 / x^(2/3)

1 /  x^(2/3)  =  -1/9

Cross multiply:  9  =  -x^(2/3)

-9  =  x^(2/3)          This means the cube root of x squared, so

cube both sides:

(-9) ^3  =  x^2

-729  =  x^2

If you are restricted to real numbers, this is impossible. However, if you can use complex numbers:

Find the square root of both sides:

x  =  ±√(-729)  =  ±27i

geno3141 Oct 29, 2014

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