Alan

Well 4747561509943 is itself 7¹⁵, so raised to the power of 7 this is 7^15*7 = 7¹⁰⁵, which is:

You can use the calculator here to find A using the tan^-1 (or atan) function (press the 2nd button on the calculator to see atan).

$${\mathtt{A}} = \underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{3}}}{{\sqrt{{\mathtt{5}}}}}}\right)} \Rightarrow {\mathtt{A}} = {\mathtt{53.300\: \!774\: \!799\: \!51^{\circ}}}$$

This is the result in the 1st quadrant.  tan is also positive in the third quadrant so you could also add 180° to the above to get another value within the range 0° to 360°

You would need to know the shape of the curvy boundary.  If it were acceptable to approximate this by a series of straight lines you would still need to know the lengths of the vertical lines at each letter.

I'm not sure I agree with Chris here.  If the question is asking what is the probability of getting exactly one ace, then my reasoning would be:

prob of 1st card being an ace = 4/52

prob of 2nd card not being an ace = 48/51

so prob of "ace" followed by "not ace" = (4/52)*(48/51)

prob of 1st card not being an ace = 48/52

prob of 2nd card being an ace = 4/51

so prob of "not ace" followed by "ace" = (48/52)*(4/51)

Overall prob of exactly one ace = (4/52)*(48/51) + (48/52)*(4/51)

$$\left({\frac{{\mathtt{4}}}{{\mathtt{52}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{48}}}{{\mathtt{51}}}}\right){\mathtt{\,\small\textbf+\,}}\left({\frac{{\mathtt{48}}}{{\mathtt{52}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{4}}}{{\mathtt{51}}}}\right) = {\frac{{\mathtt{32}}}{{\mathtt{221}}}} = {\mathtt{0.144\: \!796\: \!380\: \!090\: \!497\: \!7}}$$

If the question is what is the probability of at least one ace then:

prob of 1st card not an ace = 48/52

prob of 2nd card not an ace = 47/51

prob of at least one ace = 1 - (48/52)*(47/51)

$${\mathtt{1}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{48}}}{{\mathtt{52}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{47}}}{{\mathtt{51}}}}\right) = {\frac{{\mathtt{33}}}{{\mathtt{221}}}} = {\mathtt{0.149\: \!321\: \!266\: \!968\: \!325\: \!8}}$$

I think the question is: What is 1000lb in tons?  This is followed by a list of possible answers.

In fact 1000lb = 1/2 ton (1/2 is one of the possible values appearing in the list).

If you're old enough you might even remember a TV series called Route 66 (starring George Maharis, I think)! Its theme tune was a big hit.

There is no biggest number; numbers go on forever! 

(x-1)² + (y-1)² = 4²  Expand and rearrange to see that this is the same as your equation.

center = (1, 1) radius = 4

For minutes you must enter degrees/60; for seconds enter degrees/3600; for gradians enter degrees/0.9

$$100*v_1^n=200*(5v_1)^n\\\\
100*v_1^n=200*5^n*v_1^n\\\\
1=2*5^n\\\\
$ Take logs\\
$$\ln{1}=\ln{2}+n*\ln{5}\\\\

0=\ln{2}+n*\ln{5}\\\\
n=-\frac{\ln{2}}{\ln{5}}$$

$${\mathtt{n}} = {\mathtt{\,-\,}}{\frac{{ln}{\left({\mathtt{2}}\right)}}{{ln}{\left({\mathtt{5}}\right)}}} \Rightarrow {\mathtt{n}} = -{\mathtt{0.430\: \!676\: \!558\: \!073\: \!393\: \!1}}$$