Alan

$$$$\frac{40565}{105680}=\frac{1529*0.75}{n}$$\\
means that $$n=1529*0.75*\frac{105680}{40565}$$$$

Can you take it from here?

To convert from radians (which is what I assume the 0.4 and 1.6 are) to degrees, multiply by 180/pi.

So: 

$${\frac{{\mathtt{0.4}}{\mathtt{\,\times\,}}{\mathtt{180}}}{{\mathtt{\pi}}}} = {\mathtt{22.918\: \!311\: \!805\: \!232\: \!928\: \!4}}$$ 

This is 22° plus 0.9183118...°

There are 60' in 1° so 

$${\mathtt{0.918\: \!311\: \!805\: \!232\: \!928\: \!4}}{\mathtt{\,\times\,}}{\mathtt{60}} = {\mathtt{55.098\: \!708\: \!313\: \!975\: \!704}}$$

This is 55' plus 0.0987...'

There are 60'' in 1' so

$${\mathtt{0.098\: \!708\: \!313\: \!975\: \!704}}{\mathtt{\,\times\,}}{\mathtt{60}} = {\mathtt{5.922\: \!498\: \!838\: \!542\: \!24}}$$

This is 6'' to the nearest second.

Therefore 0.4 radians is 22° 55' 6'' to the nearest second.

Now you try converting 1.6 radians.

If RX/RV = R2/R4 then RX = 18*0.02 ohms or RX = 0.36 ohms.

However, since you don't indicate how RX and RV are connected relative to R1 and R2 it could be that RV/RX = R1/R2! Only you will know!

See the answer to the same question posted previously.

Just divide by the permeability of free space  μ0 = 1.2566370614×10⁻⁶Wb/A-m

$${\frac{\left({\mathtt{750}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}{\left({\mathtt{1.256\: \!637\: \!06}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{-{\mathtt{6}}}\right)}} = {\mathtt{596.831\: \!037\: \!276\: \!586\: \!447\: \!3}}$$

Relative permeability ≈ 597

The area of a triangle is given by half the base times the height.  There are an infinite number of triangles of different bases and heights that will have an area of magnitude 854.

Kinetic energy is (1/2)*mass*velocity²

$${\mathtt{ke}} = \left({\frac{{\mathtt{1}}}{{\mathtt{2}}}}\right){\mathtt{\,\times\,}}{\mathtt{0.5}}{\mathtt{\,\times\,}}{{\mathtt{1.4}}}^{{\mathtt{2}}} \Rightarrow {\mathtt{ke}} = {\mathtt{0.49}}$$

The kinetic energy is 0.49 joules

See the answer in your previous (anonymous) post.

Force (weight) is mass*acceleration, so the mass of the object is m = 5.10/9.81 kg.

Mass is the same at all heights, so when force (weight) is 3.81N the gravitational acceleration is a = 3.81/(5.10/9.81) m/s². 

$${\mathtt{a}} = {\frac{{\mathtt{3.81}}{\mathtt{\,\times\,}}{\mathtt{9.81}}}{{\mathtt{5.1}}}} \Rightarrow {\mathtt{a}} = {\mathtt{7.328\: \!647\: \!058\: \!823\: \!529\: \!4}}$$

a ≈ 7.33 m/s²

To four decimal places sin 23° is 0.3907