Here's my attempt at an analytical answer:
I should have written: This is the value of k at the minimum area. The minimum area itself is \(k\pi\)
I've just noticed something went wrong with the display of equation (3)! It should be \(xp = \frac{a^2}{a^2-b^2}\)
Like so:
Can you take it from here?
If you mean in the calculator on the home page here, then yes, e.g. typing 7! will result in 5040.
See reply at https://web2.0calc.com/questions/please-help_81386
This should help:
"Let x and y be real numbers such that 2(x^2 + y^2) = x + y + 1. Find the maximum value of x - y"
Use Pythagoras' theorem.
One leg of the right-angled triangle is r(the radius); the other leg is 4.5; the hypotenuse is (r+1.5).
The following should help you answer that:
This can be written as \(\frac{x^2}{13^2}+\frac{y^2}{5^2}=1\), so the semi-major axis is 13, the semi-minor axis is 5, and its centred on (0, 0).
As follows:
+33661 
