4over5+square rot (x+0.2-5x x being 5
1.
\(\frac{4}{5}+\sqrt{x+0.2-5x}=5\)
\(\sqrt{x+0.2-5x}=\frac{21}{5}\)
\(x+0.2-5x=\frac{441}{25}\)
\(\)
\(-4x=\frac{441}{25}-0.2\)
\(x=\frac{\frac{441}{25}-0.2}{-4}\)
\(x=-4.36=4\frac{9}{25}\)
2.
\(\frac{4}{5}+\sqrt{x+0.2-5x*x}=5\)
\(\sqrt{x+0.2-5x*x}=\frac{21}{5}\)
\(x+0.2-5x*x=\frac{441}{25}\)
\(-5x^2+x =\frac{441}{25}-0.2\)
\(-5x^2+1x -17.44=0\)
a b c
\(\large x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
\(\large x = {-1 \pm \sqrt{1^2-348.8} \over -10}\) the result is complex.
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