CPhill

Yep......you're exactly correct !!!!!!

4500 ( 1 + .0725/365) ^(5*365)   = about 6465.89   (b)

Let's see, Solveit.....

P(A and B)  = P(A) * P(B)   [  if A, B  are independent events  ]

"At least one" means that we have three possibilities:

Let A  = probability that Tom passes= .3  and B = probability that  John passes = .4

Both pass  =  P (A and B)  = .3 * . 4  = .12

Tom passes, and John doesn't = P (A and not B) =.3 * .6  = .18

John passes and Tom doesn't  = P(not A and B)  = .7 * .4   = .28

Summing these, we have    .12 + .18 + .28  =  .58    (D)

I assume you want to solve for r....if so....

307.7514=3.14*r^2      divide both sides by 3.14

307.7514 / 3.14  =  r^2        take the square root of each  side

r = 9.9

I believe the answer is :

30/.25  = $120

75% of the price  (profit)  = $90........25% of the price (cost)   = $30

Very nice, guest......I would have never seen that......!!!!!!

C(200,184)* (.92)^184 * (.08)^16  = about .103  = about 10.3%

y=-2(x+3) * (x-4) * (x+4)

x intercepts  = -3, 4 and -4

y intercepts   -2(3)(-4)(4)  = 96    [ (0, 96) ]

leading coefficient  = -2

degree of y  = 3

end behavior ......quadrant 2  as x approaches negative infinity.......quadrant 4 as x approaches positive infinity

Here's the graph..........https://www.desmos.com/calculator/sx8ytyafss

x / 6.25 =  1 / 1.25     cross-multiply

1.25x  =  6.25      divide both sides by 1.25

x = $5.00       (C)

No prob....