CPhill

10

The nth term is given  by :

64 (1/4)^n-1

so.....the 10th term is    64 (1/4)^{10 - 1}  =  64 (1/4)⁹  = 1 / 4096

11      35   ___    875

875 / 35   = r^2

25  = r^2       take both  roots

5  = r    or  - 5  = r

So ......the missing term is   35 * (5)  = 175 

Or......the missing term is  35 (-5)  =  -175

8.  To find the missing term, we can find the constant additive, C, as

22 + C  =    34  - C        add C to both  sides.....subtract 22 from each side

2C  =  34 - 22

2C  = 12       divide both sides by 2

C  = 6

So.....the missing term is  22 +  6    = 28

9.   

1/3    2/9      4 /27......

Notice that each successive term is forund by multiplying the current term by 2/3

(First answer )

6....Definitely not.....the difference  between  the terms is not an additive/subtractive  constant

7.   

 20  16  12 

The nth term is given by

20  - 4 (n - 1)

So....the 12th  term is

20 - 4(12 - 1)  =

20 - 4(11)  =

20 - 44  =

-24 

Thanks....i appreciate that  !!1

4.

The height after the nth bounce is  given by :

8  * ( .80 )ⁿ

So.....after the 3rd bounce we have

8 * (.80) ³  =   4.1  ft

5. The bacterium increases by 24  every hour......so the function is

a_n  =  24n

percent error = l measured value - true value l  / true value x 100%  =

l 24  - 30 l  /  30  x 100%  =

l 6  l  / 30  x 100%  =

(6/30) x 100%  =

(1/5) x 100%  =

100% / 5  =

20%

The last one is correct

Omi  answered the second one in your earlier post

For the first  one

1:  A square and an equilateral triangle have equal perimeters. The area of the triangle is 2 sqrt 3 square inches. What is the number of inches in the length of the diagonal of the square?

Area  of triangle  is given by

2sqrt (3)  =  (1/2) side^2  * sin (60)

2 sqrt (3)  =  (1/2)side^2  * sqrt (3) / 2       simplify

2  = side^2 / 4

8  = side^2

√8  = side

So....the perimeter of the triangle   = 3√8  in

So.......the  side of the square  =  1/4  of this   =  (3/4)√8  in

And the diagonal  is √2  of this  =  √2 *  (3/4) √8  =   (3/4) * √16  in  =

(3/4)* 4   =    3 in

1.   10  -80    640    -5120

a_n  = 10 (-8)^n-1

2.  (1/2)(4/3) ^n-1

a₁  = (1/2),  a_n   = (4/3)a_n-1

1.  The first term is 7.....only one answer has a first term  = 7

2.

8, 6, 4 , 2

The difference  in the successive term  to the previous term  is -2

And the first term is 8

So we have

a₁  = 8 , a_n  = a_n-1 - 2     ⇒  first answer

3.  

-3, 1, 5 ,9

a_n   =  -3  + 4(n - 1) ⇒  first answer