a) y = x^2 + 3 subtract 3 from both sides
y - 3 = x^2 take both roots
±√ [ y - 3 ] = x "swap" x and y
±√[ x - 3] = y Note, GM.....this is the inverse.....but not an inverse "function".....since the original function isn't one-to-one.....then we don't have a true inverse function
b) y = [ (1/4)x + 6 ] ^3 take the cube root of both sides
∛y = (1/4)x + 6 subtract 6 from both sides
∛[y] - 6 = (1/4) x multiply through by 4
4 ∛[y] - 24 = x swap x and y
4 ∛[x] - 24 = y = the inverse