Here's my best effort
(1/2) the area of one of the larger "leaves" is
The area of a sector with a 120° arc and a radius of 4 less the area of a triangle with sides of 4 and an included angle of 120° =
(1/2) 4^2 (2pi/3) - (1/2)(4)^2 sin (120°) =
(1/2) 16 ( 2pi/3 - √3/2) =
8 ( 2pi/3 - √3/2)
And we have 6 of these areas (2 per leaf)
So the area of all three larger leaves = 6 * 8 ( 2pi/3 - √3/2) = 48 (2pi/3 - √3/2) = 96 pi/3 - 24√3 (1)
From this....we must subtract the total area of the smaller two "leaves"
(1/2) of the area of one of these =
Area of a sector with a 60° arc and a radius of 4 less the area of a triangle with sides of 4 and an included angle of 60° =
(1/2) (4^2) (pi/3) - (1/2)(4^2) sin 60° =
(1/2)(4^2) [ pi/3 - √3/2] =
8 [ pi/3 - √3/2]
And we have 4 of these areas
So the total area of the smaller two leaves = 32 [ pi/3 - √3/2] = 32pi/3 - 16√3 (2)
Total shaded area = (1) - (2) = 96pi/3 -24√3 - [ 32pi/3 - 16√3 ] =
[64pi/3 - 8√3] units^2