Let's see...we need two integers that multiply to 2 = 1, 2
And 2 two integers that multiply to 6 = 1, 6 or 3,2
Every term is positive...so no negatives will apply
So....let's try
(2x + 3) ( x + 2) hey ....got it on the first try !!!
Proof
2x*x + 2x*2 + 3*x + 3*2 =
2x^2 + 4x + 3x + 6 =
2x^2 + 7x + 6 = just what we started with !!!