Darry

Thanks! I knew it would be something simple like that but I just couldn't figure it out lol

If you calculate the volume of the cylinder using \({h}{\pi}{r}^{2}\), you need to use the height of 6cm (instead of 8cm) because each glass is being filled 2cm from the top, making the height 6cm. You get a volume of 169.646 cubic centimeters. (which is \(54\pi\)). There are 1000 cubic centimeters in one liter, so you can quickly convert this to 0.1696 liters. Then just divide 1.5 by that volume, and you'll get 8.844 glasses filled. Because we want to fill each glass completely, we just knock off those 0.844 glasses to make it fill an even 8 glasses.

Remember that the formula for perimeter is 2L+2W. In this case, that would be 2(2x-4)+2(2x+3). If you add those numbers, you get the perimeter as 10x-2. So, the answer is C.

There can be a minumum of 6 right handed girls.

And now I'm at 29 ¯\_(ツ)_/¯

im honestly so confused

Dude I joined like 10 days ago and have less than 50 points, not to mention this is the first post by OP that I've seen, I'm not downvoting anybody

I count 10 quadrilaterals

I count 12 triangles

5.4/6=0.9

There is 0.9 pounds of coffee in each smaller bag.

Ah, thanks. I didn't completely understand what it meant by linear measurement, but now I get it.

200/3000=0.0666666666666667

If you use the formula for area of a rectangle, (Length x Height), then you get 1.13 x 2.1, which is 2.373 in².

If you enter the following sequence into the calculator:

(sqrt(x)+sqrt(1/x)-sqrt(2))/(sqrt(x)+sqrt(1/x))=(sqrt(x)+sqrt(1/x))/(sqrt(x)+sqrt(1/x)+(3*sqrt(2))

Then the answer is shown to be:

{x=0, x=(((3*sqrt(2))*sqrt(x)-2)/2)}

The answer computes to:

30126600184576595448099770

77527059692324164918673621

79905334690059666720761848

08090678606920977137619846

09779945772783965563851033

30077232629777308785186998

25002706617912441225976217

60000000000000000000000000

000000

So it ends in 31 zeroes

Its similar to if a = b and b = c, then a = c. If I is greater than M and M is greater than N, than N is less than all other variables, so N

Think about it on a number line:

I is going to be the furthest to the right, then M, then finally, N.

              N            M         I                  

low<------------------------------>high

does this fulfill our requirements? I is greater than M, M is greater than N. So, therefore, by looking at this, we can determine that N is less than I.