m = 6 kg
F= 2.4 N
x = xo + vo t + 1/2 a t^2 x0 = 0 vo = velocity original = o so:
x = 1/2 a t^2 x = 2 (given) (1)
Now a = (change in v) / (change in t) = 1.2 m/s / t (2) Substitute this into (1)
2 m = 1/2 a t^2
2m = 1/2 (1.2 m/s / t) (t^2)
2 = .6 t so t = 3.333 sec
Remember F= ma so:
F = .6 * a and a = 1.2/t and t = 3.333
F= .6 * 1.2/3.333 = 2.16 N = Net Force (East)
Frictional force is 2.4 - 2.16 N = .24 N West (or -.24 N East)