Hey Rom..... that is only a 30% increase......
Wow....looks like CHris is a bit bored! HaHa !
When the ball hits the ground, y= 0 so substitute that in to the equation and solve for t
0 = -4.9t^2+42t +18.9 Use Quadratic Formula a = -4.9 b = 42 c = 18.9
\(t = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
t=−0.428571 throw out
t=9 sec
Let x be the number
x + 1.3x = 69
2.3 x = 69
x = 69/2.3 = 30
x^2-7x <0
x(x-7) <0
so x<0 or x <7 but if x<0 the answer would be >0
so the only integers would be 1 2 3 4 5 6
x + .75x = 35
1.75x = 35
x = 35/1.75 = 20
https://web2.0calc.com/questions/help_90672
See:
https://web2.0calc.com/questions/anyone-help_3
https://web2.0calc.com/questions/help_54065
[-2,7] would be the notation