g(f (x) ) = 2(ax+b) -5 for all x , this equals 3x+4 solve for a and b
2ax+2b - 5 = 3x+4
2ax = 3x and 2b-5 = 4
a = 3/2 and b = 9/2 I think you can add these together for the answer....
Making 10 pounds
c = cashews
10-c = peanuts
(10-c) = p
c (6.5) + (10-c)(4.0) = 10 (4.75) solve for c then solve for p with the red equation
Zero IS between 1 and -1 TRUE
5 is GREATER than -3 this statement says y is LESS than -3 false
2019 - 5^4 - 6^4 = 97 = a^4 +b^4
81 +16 = a^4 + b^4
3^4 + 2^4 = a^4 + b^4
The maximum frictional force will be csf m g
If the force is greater or equal to this, the mass will slide
csf m g = ma This 'a' is the decelleration max magnitude when the mass , m , will slide
csf g = a
.75 (9.81) = 7.358 m/s^2 DEceleration
Hmmmm.... ALL 12 of my triangles have the equal side lengths of 1.....and 4 have bases 0f 3 I guess there is only two that can be found?
The question says nothing about rotating/flipping being the same triangle..... I still think there is 16.....reflected / rotated / flipped makes it another triangle in the diagram ..... IMO
Thrown horizontally....how long before it his the ground?
x = x0 + vi t+ 1/2 a t2 x = 0 xo = 36.7 m vi =0 a = -9.81 m/s2
0=36.7 + 1/2 (-9.81) t2 solve for t = 2.735 seconds
vf = vo + at
vf = 0 -9.81(2.735) = -26.83 m/s (negative because it is in downward direction) if ya just want the magnitude: 26.83 m/s
Isosceles triangles? I can find 12
(125 ft x 6 ft ) x 2 / 100 ft2/hr = 1500 ft2 / 100 ft2/hr = 15 hr
g(x) = 4 f(x)