the 9 x part compresses the sinusoid wave from 2 pi to 2pi/9 sec = ~~.70 sec
A = anne now 4 years ago Anne was A-4
K = Katie now four years ago Katie was K-4 and this = 2(A-4)
In SIX years A+6 = K
Two equations, two unknowns....solve for A and K
K-4 = 2(A-4)
(A+6)-4 = 2A-8
10 = A K = A+6 = 16 y/o
rate * TIME = DISTANCE
DISTANCE/TIME =rate
18 / 9/8 = s + c s = boat speed c = current
18 / 9/5 = s - c add the two equations together to solve for 's' then you can compute 'c' (if ya want to)
(EDITED)
Use law of cosines
a^2 + b^2 - 2ab cos (theta) = c^2 c is the distance she will have to hike a = 7.4 m b = 5 m theta =38 degrees
If you haven't signed on for a while (I do not know the length of time involved) , you get removed from the users list......you will re-appear the enext time you sign on.
x = # adults $ 7x = revenue from adults
(165-x) = # students $ 4 (165-x) = revenue from students summed = $ 795
7x + 4 (165-x) = 795 solve for x ...the number of adults, then 165-x = # students
3.2 x 103 J / 6.30 x 104 J / kg = .051 kg = 51 g
g = green beads
o = orange beads = g + 8
b = brown beads = 2 * o = 2 (g+8) summed = 96
g + g+8 + 2 (g+8) = 96
solve for g then o = g+8 and b = 2 (g+8)
You can use Tan function
Tan 78o = opp / adj opp is the height (to which you must add David's 6 ft height) and adj = 500 ft
tan 78 = opp/500 solve for opp....then add the 6 ft
Lowest common multiple of 6 and 7 is 42
so 42 years from 1997 =.......