geno3141

He studied math in grammar school, high school, and university.

After graduation, he asked one of his best friends, who studied math harder than he did, for his notes and his help.

A fundamental Pythagorean Formula for trig states that:  sin²(θ) + cos²(θ)  =  1; 

so:  sin²(36) + cos²(36)  =  1

Divide 370.46 by 1881.18 and multiply that answer by 100. You'll need to round the answer.

The question will have to be more specific.

The amount of change is found by subtracting the initial location from the final location:  103 ft - 100 ft = 3 ft.

To find the percent of change, divide the amount of change by the initial amount and multiply that answer by 100:  3 ft / 100 ft x 100  =  3%. (This is an increase.)

a) A tree diagram is hard to explain in words, but I'm not sufficiently computer literate to provide a drawing.

So:  let the diagram start at point A.

From A, there are two paths, one is a successful path to B (with value 0.75) and the other is an unsuccessful path to C (with value 0.25).

There is no path from B because there is no need to take another test.

From point C, there are two paths, one is a successful path to D (with value 0.60) and the other is an unsuccessful path to E (with value 0.40)

There are no paths from D or E.

b) The only way for a student to fail is to go from A to C (0.25) and from C to E (0.40). To find the probability for going from A to E is 0.25 x 0.40  = 0.10.

c) Since the protability of failing is 0.10, the probability of succeeding is 0.90.

The probability of all succeeding is 0.90 x 0.90 x 0.90  =  0.729.

The slope of AC is:  m  =  (5 - 0) / (8 - 2)  =  5/6.

To change a slope into an angle, use invTan.  invTan(5/6)  =  39.8° (approx).

To make a mesh every 5 cm on the 5 meter side (that is, going down):  change the 5 meters into cm, giving 500 cm.

Divide 500 cm by 5 cm, giving 100 ---> however, you must add 1 to get the correct number of threads.

Each of the 101 threads is 2 meters long ---> 202 meters.

To make a mesh every 5 cm on the 2 meter side (that is, going across):  change the 2 meters into cm, giving 200 cm.

Divide 200 cm by 5 cm, giving 40 ---> again, you must add 1 to get the correct number of threads.

Each of the 41 threads is 5 meters long --->  205 meters.

Adding, you will need at least 407 meters of cord.

50  =  x(2x + 3)

50  =  2x² + 3x

0  =  2x² + 3x - 50

Quadratic formula:  x  =  [ -b ± √( b² - 4·a·c ) ] / ( 2·a )

a = 2          b = 3         c = -50

x =  [ -3 ± √( 3² - 4·2·-50 ) ] / ( 2·2 ) 

x  =  [ -3 ± √( 409) ] / ( 4 )     4.30...   or   -5.80...

(21/30) x 90  =  (7/10) x 90  =  7 x (90/10)  =  7 x 9  =  63