geno3141

What should be done with this expression; are you to factor it?  (If so, check for a typo.)

It isn't an equation, so it can't be solved.

-2x - 4  >  8                                (Remove  -4  by adding 4 to both sides.)

-2x - 4 + 4  >  8 + 4

-2x  >  12                                    (Now divide by sides by -2, remembering that if you multiply or divide both                                                       sides of an inequaty, you must change the direction of the inequality. You                                                       keep the same direction of the inequality if you multiply or divide by a                                                             positive number and if you add or subtract.)

-2x / -2  <  12 / -2

   x  <  -6

To work this without a calculator (such as in an algebra class), write all factors with the same base.

Since the two numbers that aren't exponents are 27 and 9, write both of these in terms of 3.

27  =  3^3        and        9  =  3^2

Replace the  27  and the 9  in the original problem with these values:\ to get:

( (3^3)^3 )^2 x ( (3^2)^4 )^3

Working inside the parenthese first and remembering that you multiply exponents when you raise a power to a power:

( 3^9 )^2 x ( 3^8 )^3

Continue removing powers by multiplying exponents:

3^18 x 3^24

You now need to multiply number with the same base, so add exponents:

3^42

π is a lower case Greek letter that is used to name the value of the circumference of a circle divided by the length of the diameter of a circle.

It represents an irrational number; that is, it never stops and never continually repeats.

Any calculator can give you a good approximation of this value.

π = C / d

(-5)^4  =  (-5)(-5)(-5)(-5)  =  625

The maximum and minimum values of a function are found where the first derivatives are equal to zero.

First, find the first derivative of f(x) = 1 - x^4

     --->  f'(x)  = -4x^3

Then, set f'(x) = 0

    --->  -4x^3  = 0  ---> x = 0

This says that any maximum or minimum occurs at the point  (0,y)

At x = 0  ---> f(0)  =  1 - 0^4   --->  f(0)  = 1

Thus, the maximum or minimum occurs at  (0, 1).

To see if it is a max or a min:

Test to the left of the point (0, 1):  f'(-1)  =  -4(-1)^3  =  4  (since positive, the slope indicates that the graph is rising to the left of the point.

Test to the right of the point (0, 1): f'(1)  =  -4(1)^3  =  -4 (since negative, the slope indicates that the graph is falling to the right of the point.

Thus, the point  (0, 1) is a maximum. 

A diameter of a circle is a line segment that starts at one point on a circle, passes through the center, and end when it again reaches the circle.

In a circle, the length of a diameter is twice the length of a radius.

Distributive 17 throughout the  y² + 8y - 2    

               --->  17(y²)  +  17(8y)  -  17(2)

               --->  17y²  +  136y  -  34

So you have:    12y  +  17y²  +  136y  -  34

Combine the  12y  with the  136y

to get     17y²  +  148y  -  34

1 in  =  2.54 cm

Start by writing  x^n as e^(n lnx ).

d( x^n )/dx  =  d( e^(n lnx ) )/dx

                   =  e^( n ln x ) · d( n ln x )/dx                        chain rule

                    = x^n · ( n/x )

                    = n · x^( n - 1 )