If you use the trig identity: sin(A + B) = sin(A)cos(B) + cos(A)sin(B):
Substituting A with x and B with 30:
---> 2[ sin(x + 30) ] = 2[ sin(x)cos(30) + cos(x)sin(30) ]
Since sin(30) = 1/2 and cos(30) = √(3)/2
---> 2[ sin(x)·√(3)/2 + cos(x)·(1/2) ]
Using the distributive property with 2:
---> √(3)sin(x) + cos(x)