geno3141

(2.1 x 10^-7) x (3 x 10^-6)  =  (2.1 x 3) x (10^-7 x 10^-6)  

     =  6.3 x 10^-13                    (when multiplying numbers with the same base, add their exponents)

Save your hair; post the question ...

Enter this number into the calculator at this site and press (=).

If you need to know how to do this without a calculator, repost with that question.

Enter this number into the calculator at this site and press (=).

If you need to know how to do this without a calculator, repost with that question.

"of" is "times":

3/4  of  2/5  =  3/4 x 2/5  =  (3 x 2) / (4 x 5)  =  6/20  = 3/10

As stated elsewhere, unless you have a strange set of data that is bimodal (or trimodal), don't use the mode.

Use the mean unless you have a definite outlier, a number that is quite larger or quite smaller than the others.

Is there an outlier?

If so, use the median; if not, use the mean.

Go through the choices for the answer one at a time:

Is there a title on the graph?

Are there labels on the x-axis?

Are the numbers on the y-axis evenly spaced?

Is the first bar at a height of 15 or 25?

If you answer these questions, you will have the correct answer.

If you use the calculator at this side, type in 1.666666666 (a bunch of sixes) and hit the (=) button, it will give you the answer.

If you need to know how to do this without a calculator, post back. 

Same answer as stated before.

The usual methods to find the average are:  mean, median, and mode.

The range is not a method to find the average.

If you are specifically asked to find the mode, do so; otherwise do not use the mode to find the average.

Use the mean unless there is an outlier which will strongly influence the mean; if there is that kind of outlier, use the median.

For this data set is there an outlier (a number that is very, very much larger or smaller than the rest of the data)?

If there is, use the median, if not use the mean.

Same response as to the other question:

The usual methods to find the average are:  mean, median, and mode.

The range is not a method to find the average.

If you are specifically asked to find the mode, do so; otherwise do not use the mode to find the average.

Use the mean unless there is an outlier which will strongly influence the mean; if there is that kind of outlier, use the median.

For this data set is there an outlier (a number that is very, very much larger or smaller than the rest of the data)?

If there is, use the median, if not use the mean.