This problem is a Pythagorean Theorem problem, I assume?
- The rope is the hypotenuse (h = 26 yards)
- Length of the ground from the pole is side 'a' (a = 22 yards)
Thus, the set-up for this problem is:
222+b2=262
Taking these values, the next step is to square 22 and 26.
22^2 = 484
26^2 = 676
The equation after simplifying the numbers is:
484+b2=676
Now, it is necessary to isolate the 'b^2'.
(484−484)+b2=(676−484)
b2=192
Now, in order to completely isolate the 'b^2', we must take the square root of it, and in turn, 192.
√b2=√192
b=√192
The square root of 192 is 13.8564064605510183, which, when rounded to the nearest tenth, is about 13.9
@Anon: You rounded to the nearest hundredth, but you summed it up pretty well. I do have a habit of extracting it to the barebones 