The terms will be 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32, 35, 38, 41.
Adding with the sum of series formula we get:
14(2+41)/2
=14(43)/2
=301
I know, I did see it, but the person who answered it simply gave the answer only. I had no idea how they got it so I want a step by step explanation. Can anybody else help me?
The odd integers in this set are 1, 3, 5, 7, and 9.
The probability of the first integer being odd is 5/9.
The probability of the second integer being odd is 4/8=1/2.
So the probability they are both odd is 5/9 * 1/2= 5/18.
Since y and \(\sqrt{x}\) are inversely proportional, this means that \(y\sqrt{x}=k\) for some constant k. Substituting the given values, when x=24 and y=15, we find that \(15\sqrt{24}=k\). Therefore, when y=3, we can solve for x:
\(\begin{align*} 3\cdot\sqrt{x}&=15\sqrt{24}\\ \Rightarrow\qquad 9x=5400\\ \Rightarrow\qquad x&=\boxed{600} \end{align*}\)
Ah okay then.
No problem.
Thanks for some guidance. I do have some of this problem done but I'm just stuck right now. Hopefully this will help. Also, then wouldn't triangle ACE be similar to EBA?
Also, I'm seeing a lot more relationships between the angles now that you gave me a hint.
geno, I believe you plugged in the wrong x value.
We plug in the given point into the equation Ax-3y=6.
We then have:
A(1)-3(-3)=6
A+9=6
A=-3
Unfortunately I'm stuck on this too. I tried asking for help but I was accused of cheating by another "Guest".
+781 