$${{\mathtt{10}}}^{{\mathtt{2}}} = {{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}\right)}^{{\mathtt{2}}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{6}}\\
{\mathtt{x}} = -{\mathtt{8}}\\
\end{array} \right\}$$
.
) 